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October 19, 2006

Comments

chris

Hi Shieva, you could do this in a straightforward way using lambda calculus. Basically lambda functions as a predicate-forming operator; you could use it to form the predicate 'is such that metaphysics is beautiful' and predicate this property of Sheiva. It would be 'lambda x (metaphysics is beautiful x) Sheiva'. Btw, thanks so much for organizing the MTL conference; it was awesome!!

Lewis Powell

Chris, if one generates the predicate that way, would the resulting function 'Lambda x(metaphysics is beautiful x)', just be a constant function?

chris

Why so?

Lewis Powell

Because it doesn't vary with different values of X. If anyone is such that metaphysics is beautiful, then everyone is such that metaphysics is beautiful.

Otherwise the original quantification wouldn't have been vacuous.

chris

It depends on what it takes for something to be such that metaphysics is beautiful. But the question wasn't what it takes for it to be true; it was about how to translate the sentence. As far as I can tell, lambda abstraction does the trick. Is it the translation that you object to?

Lewis Powell

I don't object to anything, I just wanted to make sure I was understanding that if we thought that nothing about me contributes to whether or not I am such that metaphysics is beautiful, then the lambda abstraction would express a constant function (either from any X to true, or from any X to false).

chris

Oh sorry; I misunderstood. What you say sounds right to me, but the translation seems consistent with someone having a weird view of what it takes to have the propery; one that does not have it that the predicate expresses (or denotes, whatever) a constant function. But I agree with you that some such account seems to be required in order to capture the vacuousness.

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